By Sanjit Mitra
«Digital sign Processing: A Computer-Based procedure» is meant for a two-semester path on electronic sign processing for seniors or first-year graduate scholars. in response to consumer suggestions, a few new themes were extra to the second one version, whereas a few extra issues from the 1st variation were got rid of. the writer has taken nice care to arrange the chapters extra logically by means of reordering the sections inside chapters. extra worked-out examples have additionally been integrated. The ebook includes greater than 500 difficulties and a hundred and fifty MATLAB workouts.
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Extra info for A Computer-Based Approach Digital Signal Processing
H +h +h calculations. 17 37 F o r the circuit given, show that the superposi tion principle holds for the current through JK . - /? 20ft 3 en? I' "T_ 1 1. T h e superposition principle states that the currents I\ and J , as shown below, will add u p t o J. 2 5ft 20 ft -wv- 5ft 5& 2012 IOV:j; i\ ^6ft M 56FT 1-=-50V N o t e that in each case, the other voltage source was replaced b y a short circuit. 2. Calculate I from the original diagram first, using branch currents. T h e equations b e c o m e 10 - 57 - 67 = 0 50 - 207 - 4 67 = 0 h - 7 = 0 3 7 - + -L -20ft + • 5ft-aw- ~H~ A IOV-=- / + -L -=-50V |6ft J" 4 Ordering the equations: 67 + 5 7 10 3 67 + 207 7 h - U 4 50 0 Solving for 7 : 10 50 0 5 0 -1 0 20 -1 6 6 1 5 0 -1 0 20 -1 = - amp 3 .
In this m e t h o d the v e c t o r is written in terms of its components along the real and imaginary axes. T h e component along the imaginary axis is multiplied b y j = This is an excellent bookkeeping device t o keep the components separated. In order t o obtain the final answers, namely, magnitude and direction for the vectors, several operations must first b e defined. First of all, the vector is identified b y stating its components along the real and imaginary axes. T h e vector / in Fig.
26 / D C Circuits tions. It does not matter whether positive or negative current is chosen, as long as only one of these is used throughout the problem. Also, more remarkable, the true direction of the current chosen need not b e known. A n y direction m a y be chosen. If the direction chosen is wrong, the answer will have the correct magnitude for I, but it will b e preceded b y a minus sign. If the direction chosen is correct, the sign for J will b e positive. T h e use of current direc tions will b e illustrated in Sees.